-16x^2+32x=-240

Solution for -16x^2+32x=-240 equation:

-16x^2+32x=-240

We move all terms to the left:

-16x^2+32x-(-240)=0

We add all the numbers together, and all the variables

-16x^2+32x+240=0

a = -16; b = 32; c = +240;
Δ = b2-4ac
Δ = 322-4·(-16)·240
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-128}{2*-16}=\frac{-160}{-32}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+128}{2*-16}=\frac{96}{-32}
=-3
$